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Convert regularity inside L to help you regularity during the mL therefore, the units to have thickness (g mL -step one ) would be consistent:

Convert regularity inside L to help you regularity during the mL therefore, the units to have thickness (g mL -step one ) would be consistent:
(ii) Have you ever utilized the proper number of extreme data? thickness (step one.03 ) has step three tall data frequency (1) keeps 1 extreme profile When multiplying or isolating, what number of tall numbers regarding the result is a comparable once the least level of extreme data about terms and conditions utilized, so we was justified in using step one significant profile. The respond to (ten30) has actually 4 high numbers! Once the we are just justified in using 1 significant shape, we could give the answer while the a lot of g, but the best solution is to try to explore medical notation and build 1 ? 10 3 grams

(iii) Will be your address plausible? Do a great “rough” calculation: thickness ≈ step one grams mL -1 step 1 mL away from whole milk features scores of on the step 1 g step 1 L (a thousand mL) from milk possess a mass of in the a thousand ? 1 = a thousand g Because this crude formula is nearly the fresh carefully determined worth for mass our company is fairly positive that all of our address is right.

Matter 5. At 25°C and you can step one automatic teller machine stress, diamond has actually an occurrence off 3.5 g cm -step three . Assess the quantity inside cm step 3 from 0.fifty g from diamond in the twenty five°C and step 1 automatic teller machine pressure.

3.5 g cm -step three ? V (cm step three ) = V(cm step three ) ? 0.50 g ? V (cm step three ) step three.5 g cm -step 3 ? V (cm step three ) = 0.50 grams

[ step 3.5 grams cm -step three ? V (cm step three )] ? step 3.5 g cm -step three = 0.fifty g ? step 3.5 grams cm -step three V (cm step 3 ) = 0.50 ? step three.5 (cm -step 3 ) = 0.fourteen cm 3

Carry out a beneficial “rough” calculation: occurrence ≈ 5 grams cm -step 3 step one cm -step 3 away from diamond have scores of in the 5 g

(ii) Have you utilized the best number of high data? thickness (step three.5) provides dos significant data volume (0.50) have 2 high data When multiplying otherwise isolating, just how many significant figures regarding result is the same because least level of extreme numbers on the terms utilized, so we was warranted in making use of 2 extreme data. Our respond to (0.14) provides 2 extreme data

(iii) Is your answer plausible? 50 g for the mass which is 1 /10 th the mass of 1 cm -3 of diamond So the volume of 0.50 g of diamond will 1 /10 th the volume that is V = 1 /10 ? 1 cm 3 = 0.1 cm 3 Since this “rough” answer is about the same as our carefully calculated answer we are reasonably confident that our answer is correct.

Matter six. In the 25°C and you can step one automatic teller machine stress, ethylene glycol possess an occurrence of 1.11 grams mL -step 1 . Estimate the volume during the mL of 0.025 kilogram off ethylene glycol at 25°C and step one atm stress.

Convert bulk inside kg to help you size within the grams in order to remain consistent that have systems regarding thickness (g mL -1 ):

V (mL) ? step 1.eleven (g mL -1 ) = V (mL) ? twenty-five (g) ? V (mL) V (mL) ? 1.eleven (g mL -step 1 ) = twenty-five (g)

Practical question gives us 0

[V (mL) ? step 1.eleven (grams mL -1 ) ] ? step one.11 (grams mL -step 1 ) = twenty five (g) ? 1.eleven ( g mL -step one ) V (mL) = twenty five ? step one.11 (mL -step 1 ) = 23 mL

(ii) Have you made use of the best level of extreme numbers? size (0.025) provides dos tall numbers density (step 1.11) keeps 3 significant figures Whenever multiplying or separating, what number of extreme numbers on result is a comparable since the very least quantity of tall figures from the terms and conditions put, therefore we is warranted in using dos significant figures. All of our answer (25) has 2 extreme figures

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